Thursday, March 19, 2009

HOMEWORK BOUND METHOD

DI KAWASAN XYZ HENDAK DILAKSANAKAN PERENCANAAN JALAN RAYA KELAS I, DIMANA NILAI LER DARI PENGUKURAN LAPANGAN ADALAH 4000 KENDARAAN. DIKETAHUI NILAI CBR BASE ADALAH 65%, CBR SUB-BASE 25%, DAN CBR TANAH DASAR ADALAH 4%. TENTUKAN NILAI TEBAL PERKERASAN JALAN TERSEBUT ( D1, D2 DAN D3 ) !.
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25 comments:

septian cripsi pratama said...

Diket :
Po = 7
h = 4000 Log = 3.60

hb=D1
=20√Po(1+0.7*Log4000)∕CBR Base
=20 √ 7(1+0.7*3.602)∕65
= 12.32 cm

hsb=D1+D2
=20 √ Po(1+0.7*Log4000)∕CBR Sub Base
=20 √ 7(1+0.7*3.602∕25
=19.86 cm yg di pakai = 25 cm

12.32 + D2 = 19.86 D2 = 7.54 cm

htd =D1 + D2 + D3
= 20 √ Po(1+0.7*Log4000)∕CBR Tanah Dasar
= 20 √ 7(1+0.7*3.602∕4
= 49.65 cm
12.32 + 7.54 + D3 = 49.65
D3 = 49.65 – 12.33 – 7.54
= 29.79 cm

March 22, 2009 at 10:19 PM
Alfian Eka H Y said...

Diket :
Po = 7
h = 4000 Log = 3.60

hb=D1
=20√Po(1+0.7*Log4000)∕CBR Base
=20 √ 7(1+0.7*3.602)∕65
= 12.32 cm

hsb=D1+D2
=20 √ Po(1+0.7*Log4000)∕CBR Sub Base
=20 √ 7(1+0.7*3.602∕25
=19.86 cm yg di pakai = 25 cm

12.32 + D2 = 19.86 D2 = 7.54 cm

htd =D1 + D2 + D3
= 20 √ Po(1+0.7*Log4000)∕CBR Tanah Dasar
= 20 √ 7(1+0.7*3.602∕4
= 49.65 cm
12.32 + 7.54 + D3 = 49.65
D3 = 49.65 – 12.33 – 7.54
= 29.79 cm

March 22, 2009 at 10:21 PM
Thomas Arya P. said...

Diket :
Po = 7
h = 4000 Log = 3.60
dit : D1,D2,D3

jawab :
hb=D1
=20√Po(1+0.7*Log4000)∕CBR Base
=20 √ 7(1+0.7*3.602)∕65
= 12.32 cm

hsb=D1+D2
=20 √ Po(1+0.7*Log4000)∕CBR Sub Base
=20 √ 7(1+0.7*3.602∕25
=19.86 cm yg di pakai = 25 cm

12.32 + D2 = 19.86
D2 = 7.54 cm

htd =D1 + D2 + D3
= 20 √ Po(1+0.7*Log4000)∕CBR Tanah Dasar
= 20 √ 7(1+0.7*3.602∕4
= 49.65 cm

12.32 + 7.54 + D3 = 49.65
D3 = 49.65 – 12.33 – 7.54
D3 = 29.79 cm

March 22, 2009 at 10:29 PM
Achmad Hannafi said...

Diket :
Po = 7
h = 4000 Log = 3.60
dit : D1,D2,D3

jawab :
hb=D1
=20√Po(1+0.7*Log4000)∕CBR Base
=20 √ 7(1+0.7*3.602)∕65
= 12.32 cm

hsb=D1+D2
=20 √ Po(1+0.7*Log4000)∕CBR Sub Base
=20 √ 7(1+0.7*3.602∕25
=19.86 cm yg di pakai = 25 cm

12.32 + D2 = 19.86
D2 = 7.54 cm

htd =D1 + D2 + D3
= 20 √ Po(1+0.7*Log4000)∕CBR Tanah Dasar
= 20 √ 7(1+0.7*3.602∕4
= 49.65 cm

12.32 + 7.54 + D3 = 49.65
D3 = 49.65 – 12.33 – 7.54
D3 = 29.79 cm

March 22, 2009 at 10:30 PM
Mirawati S said...

Diket :
Po = 7
h = Log 4000 = 3.602
ditanya :
D1,D2,D3....?
jawab :

hb=D1
=20√Po(1+0.7*Log4000)∕CBR Base
=20 √ 7(1+0.7*3.602)∕65
= 12.3 cm

hsb=D1+D2
=20 √ Po(1+0.7*Log4000)∕CBR Sub Base
=20 √ 7(1+0.7*3.602)∕25
=19.9 cm yg di pakai = 25 cm

jadi
D2 = 25 - 12.3
D2 = 12.7 cm

htd =D1 + D2 + D3
= 20 √ Po(1+0.7*Log4000)∕CBR Tanah Dasar
= 20 √ 7(1+0.7*3.602∕4
= 49.6 cm

jadi
D3 =49.6 - 25
=24.6 cm
D3 = 49.65 – 12.33 – 7.54
= 29.79 cm

March 22, 2009 at 10:39 PM
destriawan santoso said...

Diket :
Po = 7
h = Log 4000 = 3.602
ditanya :
D1,D2,D3....?
jawab :

hb=D1
=20√Po(1+0.7*Log4000)∕CBR Base
=20 √ 7(1+0.7*3.602)∕65
= 12.3 cm

hsb=D1+D2
=20 √ Po(1+0.7*Log4000)∕CBR Sub Base
=20 √ 7(1+0.7*3.602)∕25
=19.9 cm yg di pakai = 25 cm

jadi
D2 = 25 - 12.3
D2 = 12.7 cm

htd =D1 + D2 + D3
= 20 √ Po(1+0.7*Log4000)∕CBR Tanah Dasar
= 20 √ 7(1+0.7*3.602∕4
= 49.6 cm

jadi
D3 =49.6 - 25
=24.6 cm
D3 = 49.65 – 12.33 – 7.54
= 29.79 cm

March 22, 2009 at 10:43 PM
Diyana eka Kartika S said...

Diket :
Po = 7
h = Log 4000 = 3.602
ditanya :
D1,D2,D3....?
jawab :

hb=D1
=20√Po(1+0.7*Log4000)∕CBR Base
=20 √ 7(1+0.7*3.602)∕65
= 12.3 cm

hsb=D1+D2
=20 √ Po(1+0.7*Log4000)∕CBR Sub Base
=20 √ 7(1+0.7*3.602)∕25
=19.9 cm yg di pakai = 25 cm

jadi
D2 = 25 - 12.3
D2 = 12.7 cm

htd =D1 + D2 + D3
= 20 √ Po(1+0.7*Log4000)∕CBR Tanah Dasar
= 20 √ 7(1+0.7*3.602∕4
= 49.6 cm

jadi
D3 =49.6 - 25
=24.6 cm
D3 = 49.65 – 12.33 – 7.54
= 29.79 cm

March 22, 2009 at 10:44 PM
mei suci wulan.s said...

Diket :
Po = 7
h = 4000 Log = 3.60

hb=D1
=20√Po(1+0.7*Log4000)∕CBR Base
=20 √ 7(1+0.7*3.602)∕65
= 12.32 cm

hsb=D1+D2
=20 √ Po(1+0.7*Log4000)∕CBR Sub Base
=20 √ 7(1+0.7*3.602∕25
=19.86 cm yg di pakai = 25 cm

12.32 + D2 = 19.86 D2 = 7.54 cm

htd =D1 + D2 + D3
= 20 √ Po(1+0.7*Log4000)∕CBR Tanah Dasar
= 20 √ 7(1+0.7*3.602∕4
= 49.65 cm
12.32 + 7.54 + D3 = 49.65
D3 = 49.65 – 12.33 – 7.54
= 29.79 cm

March 23, 2009 at 12:07 AM
setyo ajeng.m said...

Diket :
Po = 7
h = 4000 Log = 3.60

hb=D1
=20√Po(1+0.7*Log4000)∕CBR Base
=20 √ 7(1+0.7*3.602)∕65
= 12.32 cm

hsb=D1+D2
=20 √ Po(1+0.7*Log4000)∕CBR Sub Base
=20 √ 7(1+0.7*3.602∕25
=19.86 cm yg di pakai = 25 cm

12.32 + D2 = 19.86 D2 = 7.54 cm

htd =D1 + D2 + D3
= 20 √ Po(1+0.7*Log4000)∕CBR Tanah Dasar
= 20 √ 7(1+0.7*3.602∕4
= 49.65 cm
12.32 + 7.54 + D3 = 49.65
D3 = 49.65 – 12.33 – 7.54
= 29.79 cm

March 23, 2009 at 12:11 AM
vishe nurdanatri said...

Diket :
Po = 7
h = 4000 Log = 3.60

hb=D1
=20√Po(1+0.7*Log4000)∕CBR Base
=20 √ 7(1+0.7*3.602)∕65
= 12.32 cm

hsb=D1+D2
=20 √ Po(1+0.7*Log4000)∕CBR Sub Base
=20 √ 7(1+0.7*3.602∕25
=19.86 cm yg di pakai = 25 cm

12.32 + D2 = 19.86 D2 = 7.54 cm

htd =D1 + D2 + D3
= 20 √ Po(1+0.7*Log4000)∕CBR Tanah Dasar
= 20 √ 7(1+0.7*3.602∕4
= 49.65 cm
12.32 + 7.54 + D3 = 49.65
D3 = 49.65 – 12.33 – 7.54
= 29.79 cm

March 23, 2009 at 12:12 AM
Dedik suhendrik p. said...

Diket :
Po = 7
h = 4000 Log = 3.60
dit : D1,D2,D3

jawab :
hb=D1
=20√Po(1+0.7*Log4000)∕CBR Base
=20 √ 7(1+0.7*3.602)∕65
= 12.32 cm

hsb=D1+D2
=20 √ Po(1+0.7*Log4000)∕CBR Sub Base
=20 √ 7(1+0.7*3.602∕25
=19.86 cm yg di pakai = 25 cm

12.32 + D2 = 19.86
D2 = 7.54 cm

htd =D1 + D2 + D3
= 20 √ Po(1+0.7*Log4000)∕CBR Tanah Dasar
= 20 √ 7(1+0.7*3.602∕4
= 49.65 cm

12.32 + 7.54 + D3 = 49.65
D3 = 49.65 – 12.33 – 7.54
D3 = 29.79 cm

March 23, 2009 at 1:38 AM
Dede sulaiman said...

Diket :
Po = 7
h = 4000 Log = 3.60

hb=D1
=20√Po(1+0.7*Log4000)∕CBR Base
=20 √ 7(1+0.7*3.602)∕65
= 12.32 cm

hsb=D1+D2
=20 √ Po(1+0.7*Log4000)∕CBR Sub Base
=20 √ 7(1+0.7*3.602∕25
=19.86 cm yg di pakai = 25 cm

12.32 + D2 = 19.86 D2 = 7.54 cm

htd =D1 + D2 + D3
= 20 √ Po(1+0.7*Log4000)∕CBR Tanah Dasar
= 20 √ 7(1+0.7*3.602∕4
= 49.65 cm
12.32 + 7.54 + D3 = 49.65
D3 = 49.65 – 12.33 – 7.54
= 29.79 cm

March 23, 2009 at 1:59 AM
Dede sulaiman said...

Diket :
Po = 7
h = Log 4000 = 3.602
ditanya :
D1,D2,D3....?
jawab :

hb=D1
=20√Po(1+0.7*Log4000)∕CBR Base
=20 √ 7(1+0.7*3.602)∕65
= 12.3 cm

hsb=D1+D2
=20 √ Po(1+0.7*Log4000)∕CBR Sub Base
=20 √ 7(1+0.7*3.602)∕25
=19.9 cm yg di pakai = 25 cm

jadi
D2 = 25 - 12.3
D2 = 12.7 cm

htd =D1 + D2 + D3
= 20 √ Po(1+0.7*Log4000)∕CBR Tanah Dasar
= 20 √ 7(1+0.7*3.602∕4
= 49.6 cm

jadi
D3 =49.6 - 25
=24.6 cm
D3 = 49.65 – 12.33 – 7.54
= 29.79 cm

March 23, 2009 at 2:22 AM
risang rukmantoro said...

Diket :
Po = 7
h = 4000 Log = 3.60
dit : D1,D2,D3

jawab :
hb=D1
=20√Po(1+0.7*Log4000)∕CBR Base
=20 √ 7(1+0.7*3.602)∕65
= 12.32 cm

hsb=D1+D2
=20 √ Po(1+0.7*Log4000)∕CBR Sub Base
=20 √ 7(1+0.7*3.602∕25
=19.86 cm yg di pakai = 25 cm

12.32 + D2 = 19.86
D2 = 7.54 cm

htd =D1 + D2 + D3
= 20 √ Po(1+0.7*Log4000)∕CBR Tanah Dasar
= 20 √ 7(1+0.7*3.602∕4
= 49.65 cm

12.32 + 7.54 + D3 = 49.65
D3 = 49.65 – 12.33 – 7.54
D3 = 29.79 cm

March 23, 2009 at 6:53 AM
yohanes said...

Diket :
Po = 7
h = 4000 Log = 3.60

hb=D1
=20√Po(1+0.7*Log4000)∕CBR Base
=20 √ 7(1+0.7*3.602)∕65
= 12.32 cm

hsb=D1+D2
=20 √ Po(1+0.7*Log4000)∕CBR Sub Base
=20 √ 7(1+0.7*3.602∕25
=19.86 cm yg di pakai = 25 cm

12.32 + D2 = 19.86 D2 = 7.54 cm

htd =D1 + D2 + D3
= 20 √ Po(1+0.7*Log4000)∕CBR Tanah Dasar
= 20 √ 7(1+0.7*3.602∕4
= 49.65 cm
12.32 + 7.54 + D3 = 49.65
D3 = 49.65 – 12.33 – 7.54
= 29.79 cm

March 23, 2009 at 7:28 AM
tito kusuma(itemz) said...

Diket :
Po = 7
h = 4000 Log = 3.60

hb=D1
=20√Po(1+0.7*Log4000)∕CBR Base
=20 √ 7(1+0.7*3.602)∕65
= 12.32 cm

hsb=D1+D2
=20 √ Po(1+0.7*Log4000)∕CBR Sub Base
=20 √ 7(1+0.7*3.602∕25
=19.86 cm yg di pakai = 25 cm

12.32 + D2 = 19.86 D2 = 7.54 cm

htd =D1 + D2 + D3
= 20 √ Po(1+0.7*Log4000)∕CBR Tanah Dasar
= 20 √ 7(1+0.7*3.602∕4
= 49.65 cm
12.32 + 7.54 + D3 = 49.65
D3 = 49.65 – 12.33 – 7.54
= 29.79 cm

March 23, 2009 at 8:26 PM
ahmad fauzi said...

Diket : Po = 7
h = 4000 Log = 3.60


hb=D1
=20√Po(1+0.7*Log4000)∕CBR Base
=20 √ 7(1+0.7*3.602)∕65
= 12.32 cm

hsb=D1+D2
=20 √ Po(1+0.7*Log4000)∕CBR Sub Base
=20 √ 7(1+0.7*3.602∕25
=19.86 cm yg di pakai = 25 cm

12.32 + D2 = 19.86 D2 = 7.54 cm

htd =D1 + D2 + D3
= 20 √ Po(1+0.7*Log4000)∕CBR Tanah Dasar
= 20 √ 7(1+0.7*3.602∕4
= 49.65 cm
12.32 + 7.54 + D3 = 49.65
D3 = 49.65 – 12.33 – 7.54
= 29.79 cm

March 23, 2009 at 8:37 PM
yayan ahmad irawan said...

Diket :
Po = 7
h = 4000 Log = 3.60

hb=D1
=20√Po(1+0.7*Log4000)∕CBR Base
=20 √ 7(1+0.7*3.602)∕65
= 12.32 cm

hsb=D1+D2
=20 √ Po(1+0.7*Log4000)∕CBR Sub Base
=20 √ 7(1+0.7*3.602∕25
=19.86 cm yg di pakai = 25 cm

12.32 + D2 = 19.86 D2 = 7.54 cm

htd =D1 + D2 + D3
= 20 √ Po(1+0.7*Log4000)∕CBR Tanah Dasar
= 20 √ 7(1+0.7*3.602∕4
= 49.65 cm
12.32 + 7.54 + D3 = 49.65
D3 = 49.65 – 12.33 – 7.54
= 29.79 cm

March 23, 2009 at 8:41 PM
HENDRI PERMANA said...

Diket :
Po = 7
h = 4000 Log = 3.60

hb=D1
=20√Po(1+0.7*Log4000)∕CBR Base
=20 √ 7(1+0.7*3.602)∕65
= 12.32 cm

hsb=D1+D2
=20 √ Po(1+0.7*Log4000)∕CBR Sub Base
=20 √ 7(1+0.7*3.602∕25
=19.86 cm yg di pakai = 25 cm

12.32 + D2 = 19.86 D2 = 7.54 cm

htd =D1 + D2 + D3
= 20 √ Po(1+0.7*Log4000)∕CBR Tanah Dasar
= 20 √ 7(1+0.7*3.602∕4
= 49.65 cm
12.32 + 7.54 + D3 = 49.65
D3 = 49.65 – 12.33 – 7.54
= 29.79 cm

March 23, 2009 at 8:54 PM
Lembaran Kata said...

nama : Rouf Priadi
npm : 0753010031



Diket :
Po = 7
h = 4000 Log = 3.60

hb=D1
=20√Po(1+0.7*Log4000)∕CBR Base
=20 √ 7(1+0.7*3.602)∕65
= 12.32 cm

hsb=D1+D2
=20 √ Po(1+0.7*Log4000)∕CBR Sub Base
=20 √ 7(1+0.7*3.602∕25
=19.86 cm yg di pakai = 25 cm

12.32 + D2 = 19.86 D2 = 7.54 cm

htd =D1 + D2 + D3
= 20 √ Po(1+0.7*Log4000)∕CBR Tanah Dasar
= 20 √ 7(1+0.7*3.602∕4
= 49.65 cm
12.32 + 7.54 + D3 = 49.65
D3 = 49.65 – 12.33 – 7.54
= 29.79 cm

March 23, 2009 at 9:07 PM
zakiyul fuad said...

Diket :
Po = 7
h = Log 4000 = 3.602
ditanya :
D1,D2,D3....?
jawab :

hb=D1
=20√Po(1+0.7*Log4000)∕CBR Base
=20 √ 7(1+0.7*3.602)∕65
= 12.3 cm

hsb=D1+D2
=20 √ Po(1+0.7*Log4000)∕CBR Sub Base
=20 √ 7(1+0.7*3.602)∕25
=19.9 cm yg di pakai = 25 cm

jadi
D2 = 25 - 12.3
D2 = 12.7 cm

htd =D1 + D2 + D3
= 20 √ Po(1+0.7*Log4000)∕CBR Tanah Dasar
= 20 √ 7(1+0.7*3.602∕4
= 49.6 cm

jadi
D3 =49.6 - 25
=24.6 cm
D3 = 49.65 – 12.33 – 7.54
= 29.79 cm

March 24, 2009 at 12:56 AM
REZA ACHDA MARTA said...

Diket :
Po = 7
h = 4000 Log = 3.60
dit : D1,D2,D3

jawab :
hb=D1
=20√Po(1+0.7*Log4000)∕CBR Base
=20 √ 7(1+0.7*3.602)∕65
= 12.32 cm

hsb=D1+D2
=20 √ Po(1+0.7*Log4000)∕CBR Sub Base
=20 √ 7(1+0.7*3.602∕25
=19.86 cm yg di pakai = 25 cm

12.32 + D2 = 19.86
D2 = 7.54 cm

htd =D1 + D2 + D3
= 20 √ Po(1+0.7*Log4000)∕CBR Tanah Dasar
= 20 √ 7(1+0.7*3.602∕4
= 49.65 cm

12.32 + 7.54 + D3 = 49.65
D3 = 49.65 – 12.33 – 7.54
D3 = 29.79 cm

March 24, 2009 at 1:35 AM
dwi istyiawan said...

Diket :
Po = 7
h = 4000 Log = 3.60

hb=D1
=20√Po(1+0.7*Log4000)∕CBR Base
=20 √ 7(1+0.7*3.602)∕65
= 12.32 cm

hsb=D1+D2
=20 √ Po(1+0.7*Log4000)∕CBR Sub Base
=20 √ 7(1+0.7*3.602∕25
=19.86 cm yg di pakai = 25 cm

12.32 + D2 = 19.86 D2 = 7.54 cm

htd =D1 + D2 + D3
= 20 √ Po(1+0.7*Log4000)∕CBR Tanah Dasar
= 20 √ 7(1+0.7*3.602∕4
= 49.65 cm
12.32 + 7.54 + D3 = 49.65
D3 = 49.65 – 12.33 – 7.54
= 29.79 cm

March 24, 2009 at 2:14 AM
sanggra umar dani said...

Diket :
Po = 7
h = Log 4000 = 3.602
ditanya :
D1,D2,D3....?
jawab :

hb=D1
=20√Po(1+0.7*Log4000)∕CBR Base
=20 √ 7(1+0.7*3.602)∕65
= 12.3 cm

hsb=D1+D2
=20 √ Po(1+0.7*Log4000)∕CBR Sub Base
=20 √ 7(1+0.7*3.602)∕25
=19.9 cm yg di pakai = 25 cm

jadi
D2 = 25 - 12.3
D2 = 12.7 cm

htd =D1 + D2 + D3
= 20 √ Po(1+0.7*Log4000)∕CBR Tanah Dasar
= 20 √ 7(1+0.7*3.602∕4
= 49.6 cm

jadi
D3 =49.6 - 25
=24.6 cm
D3 = 49.65 – 12.33 – 7.54
= 29.79 cm

March 24, 2009 at 3:31 AM
rifki.romadhoni said...

hb=D1
=20√Po(1+0.7*Log4000)∕CBR Base
=20 √ 7(1+0.7*3.602)∕65
= 12.32 cm

hsb=D1+D2
=20 √ Po(1+0.7*Log4000)∕CBR Sub Base
=20 √ 7(1+0.7*3.602∕25
=19.86 cm yg di pakai = 25 cm

12.32 + D2 = 19.86
D2 = 7.54 cm

htd =D1 + D2 + D3
= 20 √ Po(1+0.7*Log4000)∕CBR Tanah Dasar
= 20 √ 7(1+0.7*3.602∕4
= 49.65 cm

12.32 + 7.54 + D3 = 49.65
D3 = 49.65 – 12.33 – 7.54
D3 = 29.79 cm

March 24, 2009 at 8:16 PM

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