Thursday, March 19, 2009

UN-BOUND METHOD PART 2

TENTUKAN TEBAL PERKERASAN JALAN, JIKA PERENCANAAN YANG HENDAK DIBANGUN ADALAH JALAN KELAS III, DI ATAS TANAH BERPASIR, DENGAN KONDISI LALU LINTAS SEDANG !

23 comments:

Alfian Eka H Y said...

Diket:
P = 3.5 ton = 3500 kg

h= γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm

septian cripsi pratama said...

Diket:
P = 3.5 ton = 3500 kg

h= γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm

Achmad Hannafi said...

2. Diket:
P = 3.5 ton = 3500 kg
dit :
h = ..?
jawab :
h = γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm

Thomas Arya P. said...

2. Diket:
P = 3.5 ton = 3500 kg
dit :
h = ..?
jawab :
h = γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm

destriawan santoso said...

2. Diket:
P = 3.5 ton = 3500 kg
dit :
h = ..?
jawab :
h = γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm

didin hendri said...

2. Diket:
P = 3.5 ton = 3500 kg
dit :
h = ..?
jawab :
h = γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm

Dedik suhendrik p. said...
This comment has been removed by the author.
Dedik suhendrik p. said...

Dik:
P = 3.5 ton = 3500 kg

dit: h....?

jawab:

h = γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm

Dede sulaiman said...

Diket:
P = 3.5 ton = 3500 kg

h= γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm

risang rukmantoro said...

2. Diket: P = 3.5 ton
= 3500 kg
Dit : h = ..?

jawab :
h = γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm

yohanes said...

2. Diket:
P = 3.5 ton = 3500 kg
dit :
h = ..?
jawab :
h = γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm

tito kusuma(itemz) said...

2. Diket:
P = 3.5 ton = 3500 kg
dit :
h = ..?
jawab :
h = γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm

ahmad fauzi said...

Diket:
P = 3.5 ton = 3500 kg

dit : h = ..?

jawab :
h = γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm

yayan ahmad irawan said...

2. Diket:
P = 3.5 ton = 3500 kg
dit :
h = ..?
jawab :
h = γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm

HENDRI PERMANA said...

Diket:
P = 3.5 ton = 3500 kg

h= γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm

Lembaran Kata said...

nama : Rouf priadi
npm : 0753010031


Diket:
P = 3.5 ton = 3500 kg

h= γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm

zakiyul fuad said...

Diket:
P = 3.5 ton = 3500 kg

h= γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm

REZA ACHDA MARTA said...

Diket:
P = 3.5 ton = 3500 kg

h= γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm

dwi istyiawan said...

Diket:
P = 3.5 ton = 3500 kg

h= γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm

sanggra umar dani said...

2. Diket:
P = 3.5 ton = 3500 kg
dit :
h = ..?
jawab :
h = γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm

jadi tebal jalan = 20.97 cm atau 21 cm

adde desyajais said...

Diket:
P = 3.5 ton = 3500 kg
Dit:
h=...?
Jawab:
h= γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm

Hendra said...

2. Diket:
P = 3.5 ton = 3500 kg
dit :
h = ..?
jawab :
h = γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm

rifki.romadhoni said...

2. Diket:
P = 3.5 ton = 3500 kg
dit :
h = ..?
jawab :
h = γ*P / 2π*σt
= √ 2.170*3500 / 2*3.14*2.75
= 20.97 cm