I made this blog for my student
of civil engineering at civil
engineering department - UPN
Veteran Jawa Timur Surabaya
Thursday, March 19, 2009
UN-BOUND METHOD PART 2
TENTUKAN TEBAL PERKERASAN JALAN, JIKA PERENCANAAN YANG HENDAK DIBANGUN ADALAH JALAN KELAS III, DI ATAS TANAH BERPASIR, DENGAN KONDISI LALU LINTAS SEDANG !
23 comments:
Diket:
P = 3.5 ton = 3500 kg
h= γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm
Diket:
P = 3.5 ton = 3500 kg
h= γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm
2. Diket:
P = 3.5 ton = 3500 kg
dit :
h = ..?
jawab :
h = γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm
2. Diket:
P = 3.5 ton = 3500 kg
dit :
h = ..?
jawab :
h = γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm
2. Diket:
P = 3.5 ton = 3500 kg
dit :
h = ..?
jawab :
h = γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm
2. Diket:
P = 3.5 ton = 3500 kg
dit :
h = ..?
jawab :
h = γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm
Dik:
P = 3.5 ton = 3500 kg
dit: h....?
jawab:
h = γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm
Diket:
P = 3.5 ton = 3500 kg
h= γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm
2. Diket: P = 3.5 ton
= 3500 kg
Dit : h = ..?
jawab :
h = γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm
2. Diket:
P = 3.5 ton = 3500 kg
dit :
h = ..?
jawab :
h = γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm
2. Diket:
P = 3.5 ton = 3500 kg
dit :
h = ..?
jawab :
h = γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm
Diket:
P = 3.5 ton = 3500 kg
dit : h = ..?
jawab :
h = γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm
2. Diket:
P = 3.5 ton = 3500 kg
dit :
h = ..?
jawab :
h = γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm
Diket:
P = 3.5 ton = 3500 kg
h= γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm
nama : Rouf priadi
npm : 0753010031
Diket:
P = 3.5 ton = 3500 kg
h= γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm
Diket:
P = 3.5 ton = 3500 kg
h= γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm
Diket:
P = 3.5 ton = 3500 kg
h= γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm
Diket:
P = 3.5 ton = 3500 kg
h= γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm
2. Diket:
P = 3.5 ton = 3500 kg
dit :
h = ..?
jawab :
h = γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm
jadi tebal jalan = 20.97 cm atau 21 cm
Diket:
P = 3.5 ton = 3500 kg
Dit:
h=...?
Jawab:
h= γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm
2. Diket:
P = 3.5 ton = 3500 kg
dit :
h = ..?
jawab :
h = γ*P ∕ 2π*σt
= √ 2.170*3500 ∕ 2*3.14*2.75
= 20.97 cm
2. Diket:
P = 3.5 ton = 3500 kg
dit :
h = ..?
jawab :
h = γ*P / 2π*σt
= √ 2.170*3500 / 2*3.14*2.75
= 20.97 cm
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